|

|
Introduction to Chemistry
Return to Top of Page
Term List
| Chemistry |
Theory |
Derived
Unit |
Percent
Error |
|
Scientific Method |
Variable |
Volume |
Density |
|
Observation |
Experimental Control |
Metric
Prefix |
Dimensional Analysis |
|
Hypothesis |
Metric
System |
Precision |
Unit
Equality |
|
Experiment |
International System of Units (SI) |
Accepted
Value |
Conversion Factor |
|
Conclusion |
Base Unit |
Accuracy |
|
| Natural
Law |
Mass |
Significant Digit |
|
| |
|
|
|
Objectives
- Explain why a knowledge of chemistry is central to many human endeavors.
- List and describe the steps of the scientific method.
- Explain the basic safety rules that must be followed when working in the
chemistry laboratory.
- Identify the metric units of measurement used in chemistry.
- List the SI base units.
- Explain what causes uncertainty in measurements.
- Compare accuracy and precision.
- Explain how to use significant digits and scientific notation.
- Calculate percent error.
- Define density and explain how it is calculated.
- Use chemistry equations to solve problems.
- Explain how dimensional analysis and conversion factors are used to solve
problems in chemistry.
- Solve problems using dimensional analysis.
What is chemistry?
Chemistry is the study of all substances and the changes that
they undergo. Like all sciences, chemistry involves making observations
about the world and then investigating these observations. Chemistry is
part of all that we do, from the foods that we eat, to the cars that we drive.
Because chemistry touches so many areas of our lives it is often called the
Central Science. During this year we will use physics, biology, chemistry,
history, and english to learn about the processes that touch our lives everyday.
Lesson 1: The Scientific Method
Objectives
- Explain why a knowledge of chemistry is central to many human endeavors.
- List and describe the steps of the scientific method.
The Scientific Method
The scientific method is a way of answering questions about the world we live
in. The scientific method is a process that all scientists use to
investigate the observations that they make. The steps of the scientific
method are:
- Observation
- Question
- Hypothesis
- Experiment
- Conclusion
- Natural Law
- Theory
A scientist makes an observation: "Leaves on the trees are
green." The scientist takes that observation and forms a question:
"Why are the leaves on the tree green?" A hypothesis is a possible
explanation for the answer to the question. The hypothesis must be able to
be tested through experiments. If you are unable to create an experiment
then you need to develop a different hypothesis. A possible hypothesis to
our question is: "The green color of the leaves is caused by the brown soil
surrounding the trees." Now that we have an hypothesis, we must develop an
experiment. In the case of our trees, we could grow them in black
soil, brown soil, red clay, white sand, and brown sand. The independent
variable, variable that you change, is the color or type of soil. The
dependent variable, variable that changes from the experiment, is the
green color of the leaves. You would have to grow at least three trees in
each type of soil in order to verify our results using statistics. Your
experiment would either prove or disprove your hypothesis. A conclusion
is the result of our experiments. We know that our experiment would
disprove our hypothesis. The color of the soil has nothing to do with the
green color of leaves, rather, the color results from a chemical called
chlorophyll. Since our experiment disproved our hypothesis, we would have
to form a different hypothesis and a new set of experiments. Scientists
often spend their entire life searching for the answer to their question.
If a set of experiments prove your hypothesis correct, then you must develop
a new set of experiments that could be used to prove your hypothesis. If
all of your experiments prove your hypothesis correct, then you may be able to
develop a natural law, which describes how nature behaves but does not
describe why nature behaves in that particular way.
After many experiments and many different approaches to the question, the
scientist may be able to develop a theory. The theory explains why
nature behaves in the way described by the natural law. It answers not
only the original question, but also any other questions that were raised during
the process. The theory also predicts the results of further experiments,
which is how it is checked. Theories are not the end of the process.
Theories can continued to be proved or they can possibly be disproved.
Theories are not facts, but our best guess as to how the world works, based on
the scientific evidence we have collected. Many theories that we will
discuss during the year could be disproved as our understanding of the universe
continues to expand.
Lesson 2: Safety in the Laboratory
Objectives
- Explain the basic safety rules that must be followed when working in the
chemistry laboratory.
Laboratory Safety
Chemistry is a science of investigation. We will be conducting
investigations using chemicals and laboratory equipment. Before you can do
experiments in the laboratory you must understand the safety rules and
procedures.
- Follow all rules of the Teacher.
- Notify your teacher of problems.
- Know how to use the safety equipment in the laboratory.
- Wear goggles at all times
- If you have long hair, tie it back
- Avoid awkward transfers.
- If it's hot, let it cool.
- Carry chemicals defensively.
- Dispose of chemical wastes properly.
- Clean up afterward.
You will be given one warning, after that you will be asked to leave the
laboratory and will receive a zero on the lab. Safety in the laboratory is
very important, because we are not only concerned with your safety but the
safety of those around you.
Lesson 3: Units of Measurement
Objectives
- Identify the metric units of measurement used in chemistry.
- List the SI base units.
Measurements are an integral part of science. In chemistry we use a
system that is based on an international system of measurement called the
metric system.
International System of Units
In 1960, the units of the metric system were
streamlined by an international conference. The conference created a
system of units called the International System of Units, abbreviated
SI. The SI is built upon a set of seven metric units, which are called
the base units of the SI.
| SI Base Units |
|
| Physical Quantity |
Unit Name and Symbol |
| mass |
kilogram, kg |
| length |
meter, m |
| time |
second, s |
| count, quantity |
mole, mol |
| temperature |
kelvin, K |
| electric current |
ampere, A |
| luminous intensity |
candela, cd |
Derived Units
Scientists are able to use the seven base units to make or derive all other
units that are needed.
| Derived Units Commonly Used in Chemistry |
|
|
| Physical Quantity |
Unit Name and Symbol |
Units Derived From |
| area |
square meter, m2 |
meter |
| volume |
cubic meter, m3 |
meter |
| force |
newton, N |
meter, kg, second |
| pressure |
pascal, Pa |
Newton, square meter |
| energy |
joule, J |
Newton, meter |
| power |
watt, W |
Joule, second |
| voltage |
volt, V |
Watt, ampere |
| frequency |
hertz, Hz |
seconds |
| electric charge |
coulomb, C |
Ampere, second |
Volume is important in chemistry, but is not an SI unit. It is derived or made from the SI unit of meter.
A cube measuring 1 decimeter is called a liter.
Mass and weight are often used interchangeably, which is not correct. Mass is a measure of the amount of force required to move an object. All
objects have mass, even in space. Weight is a measure of the force exerted on a mass by gravity. Weight changes
depending on the amount of gravity. Our weight on earth is different than on the
moon. In space we do not have any weight.
Metric Units
| |
|
|
|
| Prefix |
Abbreviation |
Decimal |
Exponent |
| Giga- |
G |
1,000,000,000 |
109 |
| mega- |
M |
1,000,000 |
106 |
| kilo- |
k |
1,000 |
103 |
| |
|
1 |
100 |
| deci- |
d |
0.1 |
10-1 |
| centi- |
c |
0.01 |
10-2 |
| milli- |
m |
0.001 |
10-3 |
| micro- |
u |
0.000 001 |
10-6 |
| nano- |
n |
0.000 000 001 |
10-9 |
| pico- |
p |
0.000 000 000 001 |
10-12 |
| |
|
|
|
| |
|
|
|
Lesson 4: Uncertainty in Measurement
Objectives
- Explain what causes uncertainty in measurements.
- Compare accuracy and precision.
Making a measurement always involves estimating part of the number. As
we will see, part of a measurement is certain and part of a measurement is
uncertain.
Making Measurements
Instruments such as electronic balances have digital displays. The
final digit on a digital display is the estimated digit. With a digital
display, the estimation of the uncertain digit is done for you electronically.
When you record a measurement from a digital display, you will always write all
of the digits that are shown.
Instruments such as a graduated cylinder or a thermometer have scales marked
or etched on the glass. These are called analog scales and require that
you estimate the final digit in a measurement. A graduated cylinder that
has marks in 1-mL can be read to the nearest 0.1 mL. The estimated digit
is the tenth's place. You will always estimate 1/10th of the smallest
increment on the instrument.
Examples:
- Graduated cylinder: certain digit, 1-mL, estimated 0.1 m; 12.1 mL,
10.5 mL, 100.1 mL
- Beaker: certain digit 10 mL, estimated 1 mL; readings: 21 mL, 52 mL, 105
mL
- Flask: certain digit 100 mL, estimated 10 mL; reading: 110 mL, 250 mL, 310
mL
Reliability in Measurement
Precision: One way to check your work is to repeat the procedure
several times. Precision refers to the degree of agreement among several
measurements of the same quantity. If you get the same answer each time
you perform the procedure, then your work is precise. You do not have to
have the correct answer, just the same answer.
Accuracy: The second way to check your work is to compare your answer
to an accepted standard. Accuracy refers to the agreement of a particular
value with the accepted value. The closer your answer is to the accepted
value, the better your work.
You want to be both precise and accurate, but you could be precise and not
accurate, or accurate and not precise.
Lesson 5: Working With Numbers
Objectives
- Explain how to use significant digits and scientific notation.
- Calculate percent error.
- Define density and explain how it is calculated.
A measurement is rarely meaningful by itself. More commonly,
measurements are combined by adding, subtracting, multiplying, or dividing them
to produce the values of mass, volume, or temperature needed in a scientific
investigation. In this section, you are going to use several mathematical
tools to help you with this process.
Significant Digits
What is a significant digit? Significant digits tell us the precision
of your measuring device. If you use two different graduated cylinders,
one marked in 1-mL and one marked in 10-mL. The one marked in 1-mL
increments is more precise because you will be able to make the same measurement
over and over again with little difficulty. The one marked in 10-mL
increments is less precise because it will be more difficult to record the same
measurement over and over again. The one marked in 1-mL will have more
significant digits than the one marked in 10-mL increments.
When measurements are combined mathematically, the uncertainty of the
separate measurements must be correctly reflected in the final result. A
set of rules exists for this task, which depends on keeping track of the
significant digits, or significant figures, in each separate measurement.
What digits are significant in a measurement? All of the digits in a
measurement that you are certain of, plus the one that you estimate are
significant. If you are using an instrument with a digital display, all of
the digits that are shown on the display are significant. If you are using
an instrument with an analog scale, then you will have to properly estimate the
final digit for that measurement. If you have written the answer properly,
then all of the digits will be significant.
Sometimes a digit may not be significant. We have a set of rules for
you to follow when determining the number of significant figures in a
measurement.
- All non-zero digits are significant.
- Zeros that are between non-zero digits or are between significant
digits are themselves significant.
- Zeros at the beginning of a number are not significant.
- Zeros at the end of a number are significant if there is a decimal
in the number.
- Zeros at the end of a number are not significant if there is not a
decimal in the number.
- If the number is written in proper scientific notation, then all
digits listed in the mantissa are significant. The exponent is not
used when counting significant figures.
- If a number is the result of counting then we do not use that number
to determine significant figures. The number has infinite
significant figures.
- Exact number, numbers that arise from a definition, have infinite
significant figures and are not counted.
Examples:
- 256 mL
3 significant figures (See Rule 1)
- 206 V
3 significant figures (See Rule 2)
- 0.01 m
1 significant figure (See Rule 3)
- 10.00 g
4 significant figures (See Rule 4 and Rule 2)
- 120 kg
2 significant figures (See Rule 5)
- 1.230 x 1023 ug 4 significant figures (See
Rule 6)
- 1230 basketballs infinite significant figures (See
Rule 7)
- 1000 g = 1 kg
infinite significant figures (See Rule 8)
Significant Digits in Calculations
When measurements are used in a calculation, our answer cannot have more
significant figures that the single measurement with the least significant
figures. In other words your answer cannot be more precise than the least
precise measurement that was made.
Multiplication and division: Find the number with the
least number of significant figures and round your final answer to that
number of significant figures.
| Volume |
= |
length |
x |
width |
x |
height |
| |
= |
3.05 m |
x |
2.10 m |
x |
0.75 m |
| |
= |
4.80375 m3 |
|
|
|
|
| |
= |
4.8 m3 |
|
|
|
|
In the above example, the final answer has more significant figures
(six) than any number that was used to calculate the answer. The
height has two significant figures, therefore the answer is rounded to two
significant figures. Addition and Subtraction: Find the
number with the least number of decimal places and round your final answer to
that number of decimal places. Do not count significant figures.
| Shoes |
951.0 g |
| clothing |
1407
g |
| ring |
23.911 g |
|
eyeglasses |
158.18 g |
| total |
2540. g |
In the above example, the mass of the items was added together.
The final answer was rounded to zero decimal places because the mass of
the clothing did not have any decimal places listed. If a process has
both multiplication and addition, then use the rule for multiplication for
rounding your final answer. qsur = m x C x (Tf-Ti) qsur
= 75.0 g x 4.184 J/g C x (31 C - 21 C) qsur = 3138 J qsur
= 3100 J In the above example the heat of the surroundings was calculated to
be 3138 J. The temperatures used in the calculation have 2 significant
figures. The final answer should then be rounded to two significant
figures.
Scientific Notation
1,300,000 can be expressed 1.3 x 106
The number means to multiply 1.3 x 10 x 10 x 10 x 10 x 10 x 10.
Moving the decimal to the left gives a positive exponent, to the right gives
a negative exponent.
Numbers greater than 1000 and less than 0.001, should always be written in
scientific notation.
Numbers in scientific notation should have 1 nonzero number before the
decimal.
Percents and Percent Error
We will use several calculations to evaluate the accuracy of your
measurement. Percent True
Percent true is used to determine how
close you are to the accepted value. This calculation is the same as the
one that you would use for determining your grades. All values must be
greater than zero and the closer to 100% the measurement the more accurate.
|
Percent True = |
measured value |
x 100 |
| |
accepted value |
|
Percent error
Percent error is also used to determine the
accuracy of your measurement, but the closer the value is to zero the more
accurate the measurement.
|
Percent Error = |
measured
value - accepted value |
x 100 |
| |
accepted value |
|
Density
Density is one of the important properties of matter. Density is
a measurement of the amount of matter in a certain amount of space.
The formula for density is given:
The units for density are: solids (g/cm3), liquids (g/cm3
or g/mL), gases (g/L) The density of water is given as 1.00 g/mL. This
is the same as saying 1.00 g per 1.00 mL.
You need to keep this in mind when you are working with density in problems.
The units in chemistry are treated the same as if they were variables in
algebra.
|
Density of Some Common Substances |
|
Substance |
Density (g/cm3) |
|
air |
0.0013* |
| ice |
0.917 |
| water |
1.00 |
| aluminum |
2.70 |
| iron |
7.86 |
|
gold |
19.3 |
|
*at 0 C and 1 atm pressure |
Lesson 6: Solving Equations
Objectives
- Use chemistry equations to solve a problem.
Solving equations in chemistry is the same as solving equations in
algebra. It appears to be more difficult in chemistry because we do not
use "x", "y" and "z" as part of every equation
that we solve. Sometimes we will solve equations with a symbol (g, c,
t...), sometimes we will solve equations that contain words (helium, density,
pressure) and sometimes we will have equations that consist of a combination of
symbols, numbers and words. Do not make this any harder than it is.
Follow your rules for solving equations that you learned in algebra.
Example:
The equation that relates the wavelength of electromagnetic radiation to
its frequency is given below:
where
solving for frequency results in
solving for c results in
Solving equations is a simple rearrangement of the variables. It
doesn't matter the form of the variables, just that you follow the rules the
same everytime.
Equations used in Chemistry
The following are some of the equations that we will be using throughout the
year. It is not important at this time to fully understand each equation,
but to be able to recognize which equation we are using based on the information
that is given in the problem.
| Molarity (M) = |
moles
of solute |
| liters of solution |
"moles of solute" is the number of moles of the compound that is
dissolved in the solvent.
"liters of solution" is the total number of liters that the solution
occupies.
| Molality (m) = |
moles
of solute |
| kilograms of solvent |
"moles of solute" is the number of moles of the compound that is
dissolved in the solvent.
"kilograms of solvent" is the total number of kilograms of solvent
that is in the solution.
| Mole Fraction = |
moles
of substance |
| total number of moles in solution |
| Normality (N) = |
equivalents |
| liters of solution |
Lesson 7: Solving Problems
Objectives
- Explain how dimensional analysis and conversion factors are used to solve
problems in chemistry.
- Solve problems using dimensional analysis.
The majority of the work in this course involves solving problems. The
problems will revolve around laboratory situations, and will require you to
choose the correct formulas, pick the information that is important to the
problem, set up the problem correctly and to report the final answer to the
correct number of significant figures.
Number Line
The number lines below can be used to convert from one unit of
measurement to another. The first number line is used to convert
"normal" units of measurement. This is to say that the units are
not squared or cubed. If you move from the left to the right you will
divide, and moving right to left you will multiply.
Normal Measurements are based on the number 10. Each interval on a
metric number line represents 10 units.
Example 1: Convert 45 nanometers to meters.
Step 1: Counting the number of spaces from nanometers to meters, we
find that there are 9 intervals.
Step 2: Since we are moving from the left to the right, we will
divide. There were 9 intervals, so we will be dividing by 1 x 109.
Step 3: Dividing 45 by 1 x 109 gives us: 4.5 x 10-8
meters.
TI-83 Keys:
TI-83 Screen Results: 45*1E9
Example 2: Convert 3.45 Megagrams to micrograms.
Step 1: Counting the number of spaces from Megagrams to micrograms, we
find that there are 12 intervals.
Step 2: Since we are moving from the right to the left, we will
multiply. There are 12 intervals, so we will be multiplying by 1 x 1012.
Step 3: Multiplying 3.45 by 1 x 1012 gives us 3.45 x 1012
micrometers.
Example 3: Convert 24.5 mm2 to hm2.
Square units are based on the number 100 (102). Each
interval consists of 100 units.
Step 1: Counting the number of spaces from mm2 to hm2,
we find 5 intervals.
Step 2: Since we are moving from the left to the right, we will
divide. There are 12 intervals, so we will be dividing by 1 x 1005.
Step 3: Dividing 24.5 by 1 x 1005 gives us 2.45 x 10-9
hm2. Note that the answer is in proper scientific
notation.
TI-83 Keys
|
2 |
|
4 |
|
. |
|
5 |
|
÷ |
|
( |
|
1 |
|
x |
|
1 |
|
0 |
|
0 |
|
^ |
|
5 |
|
) |
Note the use of parenthesis when using the "^" symbol.
TI-83 Screen Results: 24.5/(1*100^5).
Example 4: Convert 678 cm3 to m3.
Cube units are based on the number 1000 (103). Each
interval consists of 1000 units.
Step 1: Counting the number of spaces from cm3 to m3,
we find 3 intervals.
Step 2: Since we are moving from left to right, we will divide.
There are 3 intervals, so we will be dividing by 1 x 10003.
Step 3: Dividing 678 by (1 x 10003) gives us 6.78 x 10-7
m3. Note that the answer is in proper scientific notation.

Dimensional Analysis
Dimensional analysis is a process for solving problems and for converting
from one unit to another. Once you learn how to use dimensional analysis,
you will be able to solve the majority of the problems you will encounter in
this course. In order to solve a problem using dimensional analysis you
must have or must set up unit equalities. Unit Equalities
A unit
equality is an equation that shows how different units are related.
|
Unit Equalities |
|
Metric to Metric |
|
1000 Mm = 1 Gm |
10 dm = 1 m |
1 L = 1000 cm3 |
| 1000 km =
1 Mm |
100 cm =
1 m |
1 ml = 1
cm3 |
| 1000 m =
1 km |
10 cm = 1
dm |
|
| 1000 mm =
1 m |
10 mm = 1
cm |
|
| 1000 um =
1 mm |
100 mm =
1 dm |
|
| 1000 nm =
1 um |
|
|
|
1000 pm = 1 nm |
|
|
|
English to Metric |
|
Miscellaneous |
|
1 in. = 2.54 cm |
|
1 ft = 12 in. |
| 1 gal =
3.785 L |
|
1 mi =
5280 ft |
| 1 cal =
4.184 J |
|
1 min =
60 s |
| 1 atm =
101,325 Pa |
|
1 hr = 60
min |
| |
|
1 atm = 760 mm Hg |
|
*These unit equalities follow from the definitions of the metric prefixes
and they apply to any metric unit which would use these prefixes. |
Conversion Factors
The next step in solving a problem is to write
conversion factors from the unit equality. The unit equality 1 in. =
2.54 cm can be written
|
1 in |
or |
2.54 cm |
|
2.54 cm |
|
1 in |
In a conversion factor the unit on the bottom is the unit you are starting
with, and the unit on top is the unit you are ending with. The first
conversion factor will convert centimeters to inches and the second will convert
inches to centimeters.
Solving Problems
When solving a problem make a list of what you know and what you need to
know.
It is best to start with what you are given in the problem.
Dimensional analysis is used to cancel out units not numbers. You must always
write the number and the unit when working the problem.
When solving a problem using dimensional analysis, you need to start with a
grid:
The horizontal lines are used to separate numbers from the conversion factor
and represent the mathematical operation division. The vertical lines are
used to separate different conversion factors and represent the mathematical
operation multiplication.
Example 1:
- A tile was measured to be 45.56 cm. What is the measurement in inches?
- What do we know: tile is 45.56 cm, 1 inch = 2.54 cm.
- Draw a grid. In the first box write 45.56 cm. The second grid to the right
is used to convert from cm to inches. Since cm is on the top in the first
grid, we must put cm on the bottom in the second grid and inches on top. We
can cancel cm and we are left with inches.
- The answer is rounded to 4 significant figures because the number from the
problem has four, while the conversion factor is not counted because it is a
definition.
|
45.56 cm |
1 in. |
= 17.94
in. |
| |
2.54 cm |
|
Example 2:
- The mass of a lead block was measured to be 45.6 kg. What is the mass in
micrograms?
- What do we know: The mass is 45.6 kg, 1 kg = 1000 g, 1 g = 1000 mg, 1 mg =
1000 ug.
- Start with what is given, then arrange the units so they cancel.
|
45.6 kg |
1000 g |
1000 mg |
1000 ug |
= 4.56 x 1010 ug |
| |
1 kg |
1 g |
1 mg |
|
Example 3:
- If the speed limit is 65 miles/hr, what is the speed limit in
kilometers/hr.
- What do we know: 1 mi = 1760 yd 1.094 yd = 1 m 1000 m = 1 km
- Start with 65 miles = 1 hour and then arrange conversion factors to change
to kilometers/hour.
|
65 miles |
1760 yd |
1 m |
1 km |
= 88 km/hr |
|
1 hour |
1 mile |
1.094 yd |
1000 m |
|
*** Do not let mixed units such as miles/hour or g/mL or g/cm3 cause you
problems. Using this method you can work with each unit separately, but
use a clear organized approach. Example 4:
- A car is advertised to get 15 km/L, what is it in miles/gallon.
- What do we know: 1 km = 1000 m 1 m = 1.094 yd 1760 yd = 1 mi 1 L = 1.06 qt
4 qt = 1 gal
- Start with what is given in the problem (15 km/L) and then arrange
conversion factors so that the units will cancel. Convert the km to
miles and then convert liters to gallons.
|
15 km |
1000 m |
1.094 yd |
1 mi |
1 L |
4 qt |
35 miles/gallon |
|
1 L |
1 km |
1 m |
1760 yd |
1.06 gt |
1 gal |
|
A Four-Step Problem-Solving Strategy
- Analyze: Read the entire problem carefully. Identify the
unknown quantity in the problem. Organize your given information and try
to determine what is important and what is simply extra information.
- Plan: What is your approach to solving the problem going to be?
Is there an equation that you will need to use or can you simply use
dimensional analysis? How is this problem similar to other problems that
you have solved?
- Solve: Perform the mathematical steps outlined in your plan.
Check units and significant figures.
- Evaluate: Ask yourself, Does the answer make sense? Can you
follow your steps. Do the units on top match units on the bottom?
If you are going from a small unit to a large unit your answer should be
smaller. If you are going from a large unit to a small unit, then your
answer should be larger. If it doesn't make sense to you then it
probably won't make sense to me either.
Graphing
Chemists use graphs to transform rows and columns of data into a picture.
With a graph we can determine the general trend, our accuracy and/or precision
and any patterns without having to examine the individual numbers. There
is an old saying "a picture is worth a thousand words", well a graph is also
worth a thousand words. Graphs in chemistry do not have to involve all four
quadrants. Most graphs that we will use are called scatter plots or xy
graphs. XY Plots are most common in science when we want to see if there
is a direct relationship between the independent variable (x) and the
dependent variable (y). Given the data below, the table is difficult to
view, but the graph is very clear. We can see from the graph that there is
a direct relationship between temperature and volume and we can also see where
the data points do not agree with the line of best fit.
|
Measurements of the Volume of a Sample Gas at Various Temperatures |
|
Trial |
Temperature
(Celsius) |
Volume
(mL) |
|
1 |
25 |
101.3 |
| 2 |
30. |
102.2 |
| 3 |
35 |
103.4 |
| 4 |
40. |
105.0 |
| 5 |
45 |
106.7 |
| 6 |
50. |
108.4 |
| 7 |
55 |
110.0 |
| 8 |
60. |
111.5 |
| 9 |
65 |
112.9 |
| 10 |
70. |
114.2 |
Effect of Changes in Temperature on the Volume of Air in a Balloon
 All of the topics
covered in this Chapter are basic skills that you will need to be able to use
ALL YEAR. Make sure that you learn them well now because you will see them
again in future chapters and labs.
|
|